Question

Show that the function equation defined as equation is continuous on its domain, but not uniformly continuous there. Will the function be uniformly continuous on equation for any fixed c > 0?

20 Jan 2026
Answer :
Word Count : 249
Consider the function ( f : (0,\infty) \to \mathbb{R} ) defined by ( f(x)=\frac{1}{x} ). First, continuity on its domain is shown using the definition of continuity. Let ( a>0 ) be any point in ( (0,\infty) ). For any ( \varepsilon>0 ), choose ( \delta>0 ) such that [ |x-a|<\delta \quad \Rightarrow \quad \left|\frac{1}{x}-\frac{1}{a}\right|=\frac{|x-a|}{|xa|}<\varepsilon . ] Since ( a>0 ), we can restrict ( \delta \le \frac{a}{2} ), which ensures ( x>\frac{a}{2} ). Then [ \left|\frac{1}{x}-\frac{1}{a}\right|=\frac{|x-a|}{xa}\le \frac{2}{a^{2}}|x-a|. ] Choosing ( \delta=\min\left(\frac{a}{2},\frac{a^{2}\varepsilon}{2}\right) ) gives the required result. Hence ( f
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