Question
आवर्तकाल वाले निम्नलिखित आवर्ती फलन का फूरिए श्रेणी प्रसार प्राप्त करें :
के लिए।
Answer :
Word Count : 386
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दिए गए फलन के लिए फूरिए श्रेणी (Fourier series) प्राप्त करते हैं। फलन: [ f(x) = \pi^2 - x^2, \quad -\pi < x < 0 ] यहाँ केवल नकारात्मक अंतराल है, इसलिए हम इसे (2\pi)-आवर्तकाल वाली विषम विस्तारित श्रृंखला के लिए विचार करेंगे। लेकिन चूंकि फंक्शन (x^2) और (\pi^2) समानांतर हैं (even), और यह -π से 0 तक दिया है, हम सिन श्रृंखला (sine series) के लिए इसे odd extension मान सकते हैं। सामान्य फूरिए श्रेणी रूप (2π-अवधि के लिए): [ f(x) = \frac{a_0}{2} + \sum_{n=1}^{\infty} \big(a_n \cos nx + b_n \sin nx \big) ] चरण 1: (a_0) ज्ञात करें [ a_0 = \frac{1}{\pi} \int_{-\pi}^{0} (\pi^2 - x^2), dx ] [ \int_{-\pi}^{0} (\pi^2 - x^2) dx = \pi^2[x]*{-\pi}^{0} - \frac{x^3}{3}\Big|*{-\pi}^{0} = \pi^2(0 - (-\pi)) - \frac{0^3 - (-\pi)^3}{3} = \pi^3 - \frac{\pi^3}{3} = \frac{2\pi^3}{3} ] [ a_0 = \frac{1}{\pi} \cdot \frac{2\pi^3}{3} = \frac{2\pi^2}{3} ] चरण 2: (a_n) ज्ञात करें [ a_n
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