Question
) Using fourth order Taylor series method with , solve the initial value problem
upto .
Answer :
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Given (y' = f(x,y) = x + \cos y,\quad y(0)=0,\quad h=0.2). For fourth order Taylor method, [ y_{n+1}=y_n+h y'_n+\frac{h^2}{2}y''_n+\frac{h^3}{6}y'''_n+\frac{h^4}{24}y''''_n. ] First compute derivatives. [ y' = x+\cos y ] [ y'' = 1-\sin y; y' ] [ y''' = -\cos y,(y')^2-\sin y;
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