Question
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Answer :
Word Count : 186
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Skip in 10
We want to evaluate [ I = \int_0^{\infty} e^{-ax} J_0(bx) , dx, \quad a>0, \ b>0, ] where (J_0(x)) is the Bessel function of order zero. The series expansion of (J_0(bx)) is [ J_0(bx) = \sum_{n=0}^{\infty} \frac{(-1)^n (bx)^{2n}}{(n!)^2 2^{2n}}. ] Substitute this into the integral: [ I = \int_0^\infty e^{-ax} \sum_{n=0}^{\infty} \frac{(-1)^n (bx)^{2n}}{(n!)^2 2^{2n}} , dx
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