Question
Show that
Answer :
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Skip in 10
We are asked to show that [ \int_{-1}^{1} x^2 P_{n-1}(x) P_{n+1}(x) , dx = \frac{2n(n+1)}{(2n-1)(2n+1)(2n+3)} ] where (P_n(x)) are Legendre polynomials. We solve this step by step using known recurrence relations and orthogonality properties. 1. Use the recurrence relation for Legendre polynomials: [ x P_n(x) = \frac{n+1}{2n+1} P_{n+1}(x) + \frac{n}{2n+1} P_{n-1}(x) ] 2. Express (x^2 P_{n-1}(x)) in terms of Legendre polynomials: First, write (x P_{n-1}(x)) using the recurrence: [ x P_{n-1}(x) = \frac{n}{2n-1} P_n(x) + \frac{n-1}{2n-1} P_{n-2}(x) ] Multiply both sides by (x) to get (x^2 P_{n-1}(x)): [ x^2 P_{n-1}(x) = x \left( \frac{n}{2n-1} P_n(x) +
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