Question

 Solve: equation.

09 Jan 2026
Answer :
Word Count : 117
[ (D^2- D D' -2D)z=\sin(3x+4y)+e^{2x+y} ] where (D=\frac{\partial}{\partial x},;D'=\frac{\partial}{\partial y}). The complementary function is obtained from [ D^2- D D' -2D=0 ;;\Rightarrow;; D(D-D'-2)=0. ] Hence [ D=0 \quad \text{or} \quad
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