Question

 Solve: equation. 

09 Jan 2026
Answer :
Word Count : 354
Let D = ∂/∂x and D′ = ∂/∂y. The given equation is (D² + 5DD′ + 5D′²)z = x sin(3x − 2y). First find the complementary function. Assume z = e^{mx + ny}. Then the auxiliary equation is m² + 5mn + 5n² = 0. Dividing by n² (n ≠ 0), (m/n)² + 5(m/n) + 5 = 0. Let m/n = r. Then r² + 5r + 5 = 0 ⇒ r = [−5 ± √(25 − 20)]/2 = [−5 ± √5]/2. Hence m = r n, and the complementary function is z_c = φ₁(y + ((5 − √5)/2)x)
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