Question

Obtain the Laurent series expansion of the function equation about the singularity equation.

29 Jan 2026
Answer :
Word Count : 128
We want the Laurent series of [ f(z) = \frac{e^z}{(z-2)^2} ] about (z = 2). Let (w = z - 2), so (z = w + 2). Then [ f(z) = \frac{e^{w+2}}{w^2} = \frac{e^2 e^w}{w^2}. ] Expand (e^w) in its Maclaurin series: [ e^w = 1 + w + \frac{w^2}{2!} +
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