Question
Find the following limits:(i)
(ii)
Answer :
Word Count : 150
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____ _____ ______ _______ ____ ___ ________.
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Skip in 10
(i) (\displaystyle \lim_{x \to +\infty} \left( \frac{x^2}{8x^2 - 3} \right)^{1/3}) Divide numerator and denominator inside the parentheses by (x^2): [ \frac{x^2}{8x^2 - 3} = \frac{1}{8 - \frac{3}{x^2}}. ] As (x \to +\infty), (\frac{3}{x^2} \to 0), so [ \frac{x^2}{8x^2 - 3} \to \frac{1}{8}. ] Then,
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