Question
Find the approximate root of the equation using Newton-Raphson method. Perform only 3 iterations with
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Answer :
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Skip in 10
The given equation is (2x^3 = 3x + 6). Rewriting it in the form (f(x) = 0): [ f(x) = 2x^3 - 3x - 6 ] The derivative is: [ f'(x) = 6x^2 - 3 ] Using the Newton-Raphson formula: [ x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)} ] Starting with (x_0 = 2): Iteration 1: [ f(2) = 2(2)^3 - 3(2) - 6 = 16 - 6 - 6 = 4 ] [ f'(2) = 6(2)^2 - 3 = 24 - 3 = 21 ] [ x_1 =
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