Question
A particle A of mass moving along the x-axis with speed
collides elastically with a particle B of equal mass which is initially at rest. After the collision, particle A moves at an angle of
above the x-axis. Calculate the velocities of the two particles after the collision.
Answer :
Word Count : 548
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Skip in 10
We are asked to solve a 2D elastic collision problem where the masses are equal. Let’s solve it step by step. Given: * Masses: ( m_A = m_B = 2.0\ \text{kg} ) * Initial velocity: ( u_A = 5.0\ \text{m/s},\ u_B = 0\ \text{m/s} ) * Particle A moves at (\theta_A = 60^\circ) after collision. Let (v_A) and (v_B) be the speeds of particles A and B after collision, and let (\theta_B) be the angle of B with the x-axis. Step 1: Use momentum conservation Momentum is conserved in x and y directions: x-direction: [ m_A u_A + m_B u_B = m_A v_A \cos 60^\circ + m_B v_B \cos \theta_B
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