A restaurant is experiencing discontentment among its customers. It analyses that there are three factors responsible viz. food quality, service quality and interior décor. By conducting an analysis, it assesses the probabilities of discontentment with the three factors as 0.40, 0.35 and 0.25 respectively. By conducting a survey among the customers, it also evaluated the probabilities of a customer going away discontented on account of these factors as 0.6, 0.8 and 0.5, respectively. With this information, the restaurant wants to know that, if a customer is discontented, what are the probabilities that it is so due to food, service or interior décor?
Let
“A” be the case of discontentment due to food.
“B” be the case of discontentment due to service.
& “C” be the case of discontentment due to interior décor.
Now, it’s given that
P(A) = 0.40
P(B) = 0.35
P( C ) = 0.25
Let the Probability of a CUSTOMER going away discontented on account be representated as “E”.
Then, it’s given that,
P(E/A) = 0.6 ( customer going away discontented on due to food)
P(E/B) = 0.8 ( “ “ “ “ “ “
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A restaurant is experiencing discontentment among its customers. It analyses that there are three factors responsible viz. food quality, service quality and interior décor. By conducting an analysis, it assesses the probabilities of discontentment with the three factors as 0.40, 0.35 and 0.25 respectively. By conducting a survey among the customers, it also evaluated the probabilities of a customer going away discontented on account of these factors as 0.6, 0.8 and 0.5, respectively. With this information, the restaurant wants to know that, if a customer is discontented, what are the probabilities that it is so due to food, service or interior décor?
Standard normal distribution:
Bayes' Theorem
Exponential Smoothing Method
Bayes' Theorem
Statistics can prove anything’
‘Figures cannot lie’
Comment on the above two statements, indicating reasons for the existence of such divergent views regarding the nature and functions of statistics
The monthly incomes of a group of 10,000 persons were found to be normally distributed with mean equal to 
15,000 and standard deviation equal to 1000. What is the lowest income among the richest 250 persons?