Question

Using mathematical induction, prove that the sum of the squares of first 'n' natural numbers is equation.

20 Jan 2026
Answer :
Word Count : 204
For (n = 1), the sum of the squares of the first natural number is (1^2 = 1). The given formula gives (\frac{1(1+1)(2\cdot1+1)}{6} = \frac{1\cdot2\cdot3}{6} = 1). Hence the result is true for (n = 1). Assume that the formula is true for some natural number (n = k), that is, [ 1^2 + 2^2 + 3^2 + \cdots + k^2 = \frac{k(k+1)(2k+1)}{6}. ] Now consider the sum of squares up to (k+1):
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