Question

Two positively charged particles having charges equation and equation, respectively, are kept at a distance of equation from each other. Determine the force on each charge and the electric field due to each charge. Show the force and electric field vectors on appropriate diagrams. What is the resultant force at a point midway from the two charges along the straight line joining them? 

19 Jan 2026
Answer :
Word Count : 441
Let us consider two positively charged particles with charges (q_1) and (q_2), separated by a distance (r). According to Coulomb's law, the force between two point charges is given by: [ F = k \frac{|q_1 q_2|}{r^2} ] where (k = 9 \times 10^9 , \text{Nm}^2/\text{C}^2) is Coulomb's constant. Since both charges are positive, the force between them is repulsive. The electric field produced by a point charge at a distance (r) from it is defined as: [ E = k \frac{|q|}{r^2} ] The direction of the electric field is radially outward for positive charges. ### Step 1: Force on each charge The magnitude of the force on each charge due to the other is: [ F = k \frac{q_1 q_2}{r^2} ] This force acts along the line joining the charges, with each charge experiencing a repulsive force away from the other.
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