Question

Let E1, E2, E3 and E4 be arbitrary events. Write the following events in set notations:
equation i) not more than one of E1, E2, E3, E4.
equation ii) one and only one of E1, E2, E3, E4.
equation iii) E1 and at least one of E2, E3, E4.
equation iv) none of E2, E3 and E4 using E1.
equation b) Let the probability density function of r.v. X be
equation
equation and if equation and equation, find Cov(u, v). Also check the independence of u and v.

09 Jan 2026
Answer :
Word Count : 476
i) Not more than one of (E_1, E_2, E_3, E_4) means either zero or one of the events occurs. In set notation: [ (E_1^c \cap E_2^c \cap E_3^c \cap E_4^c) ;\cup; (E_1 \cap E_2^c \cap E_3^c \cap E_4^c) ;\cup; (E_1^c \cap E_2 \cap E_3^c \cap E_4^c) ;\cup; (E_1^c \cap E_2^c \cap E_3 \cap E_4^c) ;\cup; (E_1^c \cap E_2^c \cap E_3^c \cap E_4) ] ii) One and only one of (E_1, E_2, E_3, E_4) is exactly the same as the part of (i) excluding the zero-event case: [ (E_1 \cap E_2^c \cap E_3^c \cap E_4^c) ;\cup; (E_1^c \cap E_2 \cap E_3^c \cap E_4^c) ;\cup; (E_1^c \cap E_2^c \cap E_3 \cap E_4^c) ;\cup; (E_1^c \cap E_2^c \cap E_3^c \cap E_4) ] iii) (E_1) and at least one of (E_2, E_3, E_4) occurs: [ E_1 \cap (E_2 \cup E_3 \cup E_4) ] iv) None of (E_2, E_3, E_4) occurs, using (E_1): [ E_1 \cap E_2^c \cap E_3^c \cap E_4^c ] --- For part (b), the probability density function is [ f(x) = \begin{cases} 1 + x & -1 < x \le 0 \ 1 - x & 0 < x < 1 \
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