Question

Interpret the NMR spectra of the following compounds. Give the expected  values and
explain your answer.

13 Aug 2026
Answer :
Word Count : 1006
Interpretation of an NMR spectrum involves correlating the number, position, multiplicity, and integration of signals with the chemically different hydrogen or carbon environments present in an organic compound. In proton NMR (^1H NMR), the chemical shift (δ) is expressed in parts per million (ppm) relative to tetramethylsilane (TMS), which is assigned δ 0.00 ppm. The position of a signal depends mainly on the electronic environment of the nucleus, particularly the presence of electronegative atoms, π-bonds, aromatic rings, carbonyl groups and hydrogen bonding. The splitting pattern gives information about neighbouring nonequivalent protons, while integration gives the relative number of protons responsible for each signal. The spectra of the compounds referred to in the question are not included here, so exact assignment of individual signals to particular compounds cannot be made without seeing the structures or spectra. However, the expected δ values and their interpretation can be established from the characteristic proton environments normally encountered in organic compounds. Simple saturated alkyl protons generally appear in the region δ 0.8–1.5 ppm. Thus, a terminal methyl group, R–CH3, usually gives a signal around δ 0.8–1.0 ppm, whereas a methylene group, R–CH2–R, commonly appears around δ 1.2–1.5 ppm. A methine proton, R3CH, generally occurs near δ 1.4–2.0 ppm. The exact position changes according to the substituents attached to the carbon. For example, the methyl protons of ethane occur close to δ 0.9 ppm, while the methylene protons of propane occur around δ 1.3 ppm. Their multiplicities are explained by the n + 1 rule. A CH3 group adjacent to CH2 therefore normally appears as a triplet, while the CH2 group adjacent to CH3 appears as a quartet. Protons situated next to an electronegative atom are shifted downfield because the electronegative atom withdraws electron density and deshields the proton. For example, protons in R–CH2–O– groups generally occur around δ 3.3–4.0 ppm. The CH3 protons of methanol may appear around δ 3.3–3.5 ppm, whereas the O–CH2 protons of an
_________ ______ ______ __________ __________ ________ ___ ___ ________ ____.
_____ _________ _______ ______ _______.
______ ____ ____ ________ ________ __________ __________ __________.
___ ______ _______ _______ ____ ________ _____ ___ ______.
____ _________ _________ ______ _____ ________ _________.
_____ ____ ______ _________ _______.
_________ _____ ____ _____ _______ ________ ________.
________ ____ ______ ______ ________ __________ _________ ______ ____ _______ ______.
_______ ___ _____ _____ _______ ___ ________.
___ _________ _____ _______ ____ __________ ________ _______.
_______ ______ ____ ____ __________ _________ ________ __________ ________ _____ _______ _______.
________ ___ ________ _____ ________ __________ ______.
_____ _________ ____ ______ _______ __________ _________ ______ ______ ___ _______.
_________ _____ _______ ____ ______ _____ _______.
______ _____ ________ __________ _________ _________ ____ ______.
_____ _______ __________ ________ ____ _____ ___ ______ ___.
_______ ________ ___ _____ _______ _____ __________ ________ ___ _______ ______.
__________ _____ ___ _________ ____ _________ _______.
_____ __________ _________ _______ _______ ________ ____ ________ ______ _______ ________ ______.
__________ __________ __________ _________ ______ ______.
_____ __________ __________ ______ __________ _____ __________ _________.
_____ ___ __________ _____ ____ ___ __________ ____ ______ _____ ________.
______ ___ ___ __________ _______ _______ ______.
______ ______ ___ _________ _______ ___ ________.
_____ ________ _________ ___ _____ _______ ______ ___ ______ ______ ________ ___.
__________ __________ __________ ___ ________ ________ ____ __________ _________ ____ ________ _________.
___ _____ ______ ___ _____ __________.
_____ _______ _____ ______ _______.
________ ________ ____ _______ _____ ____ _______.
_________ ________ _____ ________ ____ __________ ______ ___ ________.
__________ ________ _______ ______ _______.
____ _________ _______ __________ ______ ________ ________.
_______ ___ ___ ___ ___ ____ __________ __________ __________ ___.
__________ ____ _______ _________ ___ _________ _____ _________.
_______ __________ ___ ________ _____ _______ __________.
______ ____ __________ _______ ______.
____ ____ ________ ___ ___ _____ _______ __________ ___ __________.
______ __________ _____ _______ ______.
___ ___ ____ ____ _______.
___ ___ _______ ______ _______ __________ ________ ___ ______ ____.
___ _______ ____ _______ _________ _________ _____ __________ _______ _______ _________.
_____ ____ ______ _______ ___ _________ _____ ____ ____ _________ _______.
___ ___ _______ ___ ____ ________ _______ __________ ________.
________ _________ __________ ___ _______ _______ ______ ________ ______.
_______ __________ _________ ______ ______ __________ ___ ____.
__________ ___ _______ _____ ____.
________ ________ _____ _________ ______ _______ _______ __________ ____.
____ ______ ___ ____ ______ _____ ________.
_________ __________ _________ ______ __________ ____.
_____ _____ _________ ______ ____ ___ ________ ______ ___ __________.
____ ______ _______ ____ _______ _______ __________ ___.
__________ ___ ____ ______ _____ ____ ____ ______ ________ ________ ________.
_______ _____ ________ _________ ____ ______ _________ _____.
_______ _______ _________ ___ _______.
_______ _____ __________ ___ ___ ________ _____ _________ ____.
____ ___ ______ _________ __________ ______ __________ _________ ________ ____ _____.
____ _________ ______ _______ ____ ___ ____ _____.
________ ______ _________ ________ _____ __________ _____ ____ __________ _____ ____ __________.
_________ ___ _______ ____ _____ ________ _______ ______ ________.
____ _________ _____ __________ ___ ____ ___ ___ ____.
___ ______ _________ _______ _____ __________.
___ ___ ________ ____ ____ ___.
________ _______ ________ __________ _____ ____ _______ ________ __________ ________.
____ ____ _________ ___ ______ __________ _______ _________ ______ _________.
_____ ________ ____ _____ __________ ________ _______ __________ __________ _______ ________.
_______ ____ _______ _____ __________ _______.
_____ ___ __________ ________ ____.
________ _________ _______ ______ _______ ______ _______ _____ __________.
_______ ______ _____ ________ ________ ________ _______.
_________ ___ ______ _____ ______ ___ ___ _______.
_____ _________ ________ _________ _________.
________ ________ _______ _________ ____ ______ __________ ____.
____ ______ ______ _________ _____ ___ ______ ______ _________.
______ ___ _________ _____ ________.
________ _________ _____ _________ _______ ___ _______ ________ __________ __________ _______.
__________ _____ _________ _____ ____ ________ ___ ____ ___ ________ _____ ____.
________ _______ __________ ________ ____ __________ ____ ________ __________ _____ ______.
___ ______ _________ _____ ________ ___ _______ _____ _______ ______ _______ ____.
_______ ___ ____ ________ _______ __________ ____ ________ ____ __________ _____ ___.
___ ______ _________ _____ _________ _______ _______ __________ __________ ______.
_____ ______ _____ ________ __________ ____ _____ ___ _____.
________ ___ _______ __________.
IGNOU ACADEMY
Your IGNOU journey, made easier.
  • Solved Assignments
  • Study Notes
  • Guess Papers
  • Question Papers
Skip in 10
Top
📞
Call Support Instant phone assistance IGNOU MCHE 12 2026 2027 - Interpret the NMR spectra of the following compounds. Give the expecte | IGNOU Academy
→
🟢
WhatsApp Chat Fast live messaging
→
Email Us Business enquiries & support
→