Question
In an isotope dilution analysis experiment, radiolabelled analyte with specific activity
was added. After equilibration and chemical separation
pure analyte having specific activity
was isolated. Calculate the amount of analyte in the sample.
Answer :
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Let the amount of analyte in the original sample be (x) mg. In isotope dilution analysis, the total radioactivity is conserved, so: [ \text{Total activity added} = \text{Activity in isolated analyte} ] Total activity added = activity from radiolabelled analyte + activity from sample: [ A_{\text{total}} = (15 , \text{mg}) (0.57 , \mu\text{Ci/mg}) + x (0) \quad \text{(assuming sample
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