Question

 equation

21 Jan 2026
Answer :
Word Count : 160
The given decay is a sequence of alpha decays from Uranium-234 to Polonium-210. An alpha particle (( \alpha )) consists of 2 protons and 2 neutrons, so each alpha decay reduces the mass number by 4 and the atomic number by 2. Start with ( ^{234}\text{U}
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