Question
For married couples living in a certain locality, the probability that the husband will vote in a school board election is 0.21, the probability that they both will vote is 0.15. What is the probability that
i) at least one of them will vote?
ii) neither of them will vote?
Answer :
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Skip in 10
Let (P(H)) be the probability that the husband votes, (P(W)) the probability that the wife votes, and (P(H \cap W)) the probability that both vote. We are given: [ P(H) = 0.21, \quad P(H \cap W) = 0.15 ] i) Probability that at least one of them will vote: The probability that at least one votes is: [ P(\text{at least one}) = P(H \cup W) = P(H) + P(W) - P(H \cap W) ] We are not given (P(W)) directly, but we can assume that (P(W)) is independent unless stated otherwise. However, from the data, we can solve in terms of (P(W)). Let’s
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