Question

Find the elementary divisors and invariant factors of equation.

09 Jan 2026
Answer :
Word Count : 155
We decompose the group (\mathbb{Z}*8 \times \mathbb{Z}*{12} \times \mathbb{Z}*{15}) into its primary components. Writing each modulus as a product of prime powers gives (8=2^3), (12=2^2\cdot 3), and (15=3\cdot 5). Hence the (2)-primary part is (\mathbb{Z}*{2^3}\times \mathbb{Z}_{2^2}), the (3)-primary part is (\mathbb{Z}_3\times \mathbb{Z}_3), and the (5)-primary part is (\mathbb{Z}_5). From this, the elementary divisors are obtained by listing all cyclic
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