Question

 Let equation and let equation be algebraic over F of degree m and n, respectively. Show that equation. What can you say about equation if m and n are coprime?

09 Jan 2026
Answer :
Word Count : 245
Let (F \subset K) and (\alpha, \beta \in K) be algebraic over (F) of degrees (m) and (n), respectively. That is, the minimal polynomial of (\alpha) over (F) has degree (m) and that of (\beta) over (F) has degree (n). Consider the field extension (F(\alpha, \beta)) over (F). By the tower law, [ [F(\alpha, \beta) : F] = [F(\alpha, \beta) : F(\alpha)] \cdot [F(\alpha) : F]. ] Here, ([F(\alpha) : F] = m). Also, ([F(\alpha, \beta) : F(\alpha)] \le \text{degree of minimal polynomial of }\beta \text{ over } F(\alpha)). Since (\beta) is algebraic
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