Question

Find the direction cosines of the perpendicular from the origin to the plane


equation

09 Jan 2026
Answer :
Word Count : 151
The given plane equation is: [ \mathbf{r} \cdot (6\mathbf{i} + 4\mathbf{j} + 2\sqrt{3}\mathbf{k}) + 2 = 0 ] The vector normal to the plane is: [ \mathbf{n} = 6\mathbf{i} + 4\mathbf{j} + 2\sqrt{3}\mathbf{k} ] The direction cosines of the perpendicular from the
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