Question
Evaluate
Answer :
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Let ( I = \int (7x - 2)\sqrt{3x + 2} , dx ). Use substitution: ( u = 3x + 2 \implies du = 3 dx \implies dx = \frac{du}{3} ) and ( x = \frac{u - 2}{3} ). Then ( 7x - 2 = 7\left(\frac{u - 2}{3}\right) - 2 = \frac{7u - 14}{3} - 2 = \frac{7u
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