Design and draw the circuit using op-amp to provide the output voltage obeying following relation of input voltages:
Vo = - 10V1 - 0.3 (V/dt) -2,
This is real basic, with the gain being -R1/R2. If you're not sure where that came from, look up "inverting amplifier" and I'm sure there will be lots written about this out there. Due to the feedback around the amplifier, the circuit will keep pin 2 at whatever voltage pin 3 is, which in this case is 0. Assuming a ideal opamp, the node at pin 2 has 0 impedance to 0 volts. The current flowing onto that node thru R2 is proportional to the voltage at IN. That same current must also flow thru R1 (ideal opamp, infinite input impedance), but it flows thru R1 left to right, so the right end is lower. The net effect is inversion.
Just to pick
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