Question

Differentiate between the following compounds on the basis of UV spectra. Explain
your answer.

13 Aug 2026
Answer :
Word Count : 1204
Ultraviolet (UV) spectroscopy is an important spectroscopic technique used for the identification and differentiation of organic compounds containing chromophores, conjugated systems, aromatic rings and other groups capable of absorbing ultraviolet radiation. The absorption of UV radiation causes electronic transitions from lower-energy molecular orbitals to higher-energy molecular orbitals. Since different compounds possess different electronic structures, the position and intensity of their absorption bands are characteristic and can be used to distinguish between them. The most important electronic transitions observed in organic compounds are σ → σ*, n → σ*, π → π* and n → π*. The σ → σ* transition requires very high energy and generally occurs below 200 nm, so it is of limited value for routine identification. The n → σ* transition is observed in compounds containing heteroatoms such as oxygen, nitrogen and sulfur. The π → π* transition is particularly useful for compounds containing double bonds, aromatic systems and conjugated unsaturation. The n → π* transition is commonly observed in carbonyl compounds and other molecules containing heteroatoms with lone-pair electrons. The differentiation of organic compounds on the basis of UV spectra mainly depends on λmax, absorption intensity, number of absorption bands and the effect of conjugation and substituents on the absorption maximum. λmax is the wavelength at which maximum absorption occurs. A compound with greater conjugation generally absorbs at a longer wavelength because conjugation decreases the energy difference between the ground and excited electronic states. This movement of the absorption maximum towards a longer wavelength is known as a bathochromic shift or red shift. A movement towards shorter wavelength is called a hypsochromic shift or blue shift. For example, ethene and 1,3-butadiene can be differentiated by their UV spectra. Ethene contains one isolated double bond and therefore shows a π → π* transition at a relatively short wavelength, generally below 200 nm. In 1,3-butadiene, the two double bonds are conjugated. Conjugation permits greater delocalisation of π electrons and lowers the energy required for the electronic transition. Consequently, 1,3-butadiene absorbs at a longer wavelength than ethene. Thus, the longer λmax of 1,3-butadiene provides evidence for conjugation. Similarly, isolated and conjugated carbonyl compounds can be distinguished by UV spectroscopy. A saturated ketone such as acetone possesses a carbonyl group and shows both
________ _________ __________ _______ _______.
_______ _______ _______ __________ ___ _________ _____ ____ __________ ________ _______ ______.
________ ___ ____ _______ _________ _________.
_____ ______ ________ _______ __________ __________ ____.
___ _____ _______ ________ ____ ________ _________ _________ __________ _________ __________ ___.
_____ ______ ____ ______ ______ ______ __________ _______ ____ ______ _____ ___.
_____ ______ _____ ______ ___ _______ _____ ______ ____.
____ __________ _________ ____ ________ ______ ______.
____ ____ _____ _______ ___ __________ _____ _______ ________ ________ __________.
____ _______ _____ ___ ________ ________ ___ ___ __________ ________ ________.
_____ _____ ________ _____ ________ ____ ___.
______ _______ ______ __________ __________ _____ ____ ____ _______ ____.
__________ __________ ________ ______ _______ __________ _______ ______ ____.
________ ____ ___ _________ _______ ____ _________ ___.
___ ____ _________ _______ ___.
_________ ___ ________ ___ __________ ________ _________ _____ ________ _________ ______ ______.
______ _____ ________ _______ ______ ___ ________ ____ _________ __________ ______.
__________ _______ ___ _________ _______ _________ ____ ______ ________ ________.
_______ ________ _______ _________ _______ ____ _____ _________ ______.
____ _____ ________ _______ ___ _______ ________ _____ __________ __________ _________ __________.
_____ _________ _______ ____ ______.
______ ________ _______ _____ __________ ____ _________ ____ ___ ______ ________ _________.
___ _____ _______ ________ ____ ___ ______.
_____ ______ _______ ________ ________.
________ _______ _______ _______ ________ ______ _________ ___.
________ ________ _________ _______ _______ __________ _________ ________ ___.
__________ __________ _______ _______ _____ ____ _________.
__________ ______ _________ __________ ________ ________ __________ ___ __________ ________.
________ _____ _____ ______ ___ __________.
_______ _______ _______ _____ _______ _______ _______ ___ ___.
______ ________ _______ _________ _____ ___ ________ ___ ______ ______ _______ _________.
________ _____ ________ ________ __________ ___ ________ ____ ________ ___ ________.
___ _______ _________ _________ _________ ___ ________ ______ ________ _________ ____.
____ __________ ______ _________ _________.
________ ___ __________ ______ ___ _______ _____.
_________ ____ ______ _______ ________.
_______ ____ _______ _____ _______ ___ _________ ______ __________.
______ _____ _____ ______ ______ _______ _______ __________ _________ ________ __________ _________.
__________ __________ _______ _____ __________ ______ ___.
_________ ____ ____ _________ ______.
_____ ______ ____ _________ _________ ________ ____ _________ _____ _________ _______ _________.
______ ____ _______ ____ ____.
______ ___ ______ _______ ___.
___ _____ _________ _______ _________ ______.
_________ _________ _________ ______ ________ _______ ____ ________ ______.
_______ __________ _______ _______ ___ ______ _______ _________ ______ _______ ____.
_____ ______ __________ ________ ___ ______.
_______ ________ ___ ______ ____ ___ _________ ________ _______ ______.
__________ ______ ________ ___ ____ _____ _________ _____.
____ ___ ___ ______ ___ __________.
_______ _____ __________ ________ ___ ______ _________ _____ ______.
_______ ________ __________ ________ _________ ________ _________ _________ __________.
____ ______ ___ ________ ____ _________ ________ ___ __________ __________.
___ __________ _________ _________ ________ _______ _________ __________.
__________ ___ ____ __________ _____ ___ ________ __________ _________ ________ ______ ______.
_____ _________ ________ __________ ____.
______ _____ ________ __________ ___ ______ ______ ________.
________ __________ ________ ______ __________ ___ ______ _____ __________ ________ _______.
___ __________ _______ ______ _____ ____ ______ ______ _____ __________.
______ ____ _______ ______ ___.
_______ _____ ________ ___ ________ ________ ________ ___ _____ ______.
_________ _________ __________ _______ ____ _________ _____ ________ _________ _____ __________.
___ ____ ___ ______ ____.
______ ________ _______ ______ ____ ________ ________ ___.
________ ___ ______ _____ ________ ________ _____ _______ ___ ______ ________.
_______ _____ _____ _________ ______ _________ _______ ________ _________ ________.
________ _________ ______ ________ __________ _____ _________ _______ ______ _________.
___ _______ ____ __________ ________ ____ _________.
__________ _____ _____ ____ __________ __________ _________ _____ __________ _________ ________.
_____ ______ ___ ______ ________ ______ ____ ______ ____ ______ _____.
_______ ______ ___ __________ _______ ________ ________ ____ _____.
____ _______ ________ ______ _______ _______ ____ _______ _____.
___ _______ _____ _________ _______ _______ ______ ____ _________.
________ ________ _________ ________ __________ __________ _________.
______ ________ __________ _______ _______.
________ __________ ____ _________ ______ _______ ________ _____ ______ _____ _________ ___.
_____ ___ __________ __________ ______ _________ _______ __________ _______ __________ ________.
___ _________ ____ _____ __________ ____ ______ ___ __________.
________ _________ _________ _______ _________ ___.
_______ ________ _________ _________ ______ __________ _________ ______ ____ ______.
_________ ________ _____ _____ _______ ________ ______ ___ __________ ________.
______ _____ _________ ___ _________ ______ ______.
_____ _______ ______ _________ ________ ___ _____ ___.
_____ ________ _________ ________ ___ _________ __________ _______ ___.
________ ___ _____ __________ ______ ______ __________ _____ _______ ________.
________ ________ _______ _____ _________ _________.
_______ _____ ________ ___ ____ ___.
________ ________ __________ __________ ___.
_________ _________ ___ ____ ____ ______ _______.
_______ _____ ___ _________ ____ ___ ______ ________ ________.
____ _______ _________ ____ ___ ______ ____.
_______ _______ __________ ______ ___ ______ ____ ___ _______ _________ ____.
__________ ______ _____ ___ ________ _____ _________.
____ _________ ________ ______ _____ ______ ______ ______ ______.
_________ _________ ____ __________ ____.
________ _______ _____ __________ _____ _____ ____ _______ ___ ______ ______.
____ ____ ___ ____ __________ __________.
_____ ______ ______ __________ _______.
IGNOU ACADEMY
Your IGNOU journey, made easier.
  • Solved Assignments
  • Study Notes
  • Guess Papers
  • Question Papers
Skip in 10
Top
📞
Call Support Instant phone assistance IGNOU MCHE 12 2026 2027 - Differentiate between the following compounds on the basis of UV spect | IGNOU Academy
→
🟢
WhatsApp Chat Fast live messaging
→
Email Us Business enquiries & support
→