Question
Consider the set . Define * onX by
.
Answer :
Word Count : 145
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Skip in 10
Let (X=\mathbb{R}\setminus{-1}) and define (x_1*x_2=x_1+x_2+x_1x_2) for all (x_1,x_2\in X). First note that (x_1*x_2=(1+x_1)(1+x_2)-1). Since (x_1\neq -1) and (x_2\neq -1), we have (1+x_1\neq 0) and (1+x_2\neq 0), hence ((1+x_1)(1+x_2)\neq 0), so (x_1*x_2\neq -1). Thus (X) is closed under (*).
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