Question
Consider that two ideal gases having n1 moles are n2 moles are enclosed in two separate containers at constant temperate T and pressure P. It these two gases mix, obtain an expression for the entropy of mixing per mole of mixture.
Answer :
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When two ideal gases with (n_1) and (n_2) moles are initially in separate containers at the same temperature (T) and pressure (P), the total entropy before mixing is simply the sum of the entropies of the individual gases. For an ideal gas, the molar entropy depends on volume, temperature, and pressure. When the gases are allowed to mix, each gas expands freely to occupy the total volume (V = V_1 + V_2). This expansion is an irreversible process, which leads to an increase in entropy. The change in entropy for gas 1 due to expansion from volume (V_1) to (V) is (\Delta S_1 = n_1 R \ln \frac{V}{V_1}), and for gas
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