Question
Consider a discrete model given by
Investigate the linear stability about the positive steady state N by setting . Show that nt satisfies the equation
Hence show that is a bifurcation value and that as
the steady state bifurcates to a periodic solution of period 6.
Answer :
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The positive steady state (N^*) is obtained by setting (N_{t+1}=N_t=N_{t-1}=N^*) in [ N_{t+1}=\frac{rN_t}{1+bN_{t-1}^2}, ] which gives [ N^*=\frac{rN^*}{1+b(N^*)^2}. ] Since (N^*>0), this reduces to [ 1+b(N^*)^2=r \quad \Rightarrow \quad b(N^*)^2=r-1. ] To investigate linear stability, write [ N_t=N^*+n_t,\qquad |n_t|\ll1. ] Substituting into the model gives [ N_{t+1}=\frac{r(N^*+n_t)}{1+b(N^*+n_{t-1})^2}. ] Expanding the denominator to first order, [ 1+b(N^*+n_{t-1})^2=1+b(N^*)^2+2bN^*n_{t-1}+O(n_{t-1}^2). ] Using (1+b(N^*)^2=r), this becomes [ r+2bN^*n_{t-1}. ]
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