Question
Calculate, using Weiszäcker formula, the binding energy per nucleon for .
Given:
Answer :
Word Count : 220
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Skip in 10
For the nucleus (^{235}_{92}\mathrm{U}), the mass number is (A=235), the atomic number is (Z=92), and the neutron number is (N=143). Since (Z) is even and (N) is odd, the nucleus is odd–even, so the pairing term vanishes. The semi-empirical (Weizsäcker) mass formula for the binding energy is [ B = \alpha A - \beta A^{2/3} - \delta
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