Question

equation

21 Jan 2026
Answer :
Word Count : 208
The decay of (,^{231}\text{Th} \rightarrow ,^{211}\text{Pb},) involves a mass number change from 231 to 211, which is a difference of 20. This suggests that multiple alpha ((\alpha)) decays have occurred because each (\alpha)-particle emission decreases the mass number by 4 and the atomic number by 2. Let (n) be the number of (\alpha)-decays. Then:
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