Question

हल कीजिए : equation. equation

09 Jan 2026
Answer :
Word Count : 581
दी गई अवकल समीकरण है: [ (x^2y - 2xy^2)dx - (x^3 - 3x^2y)dy = 0 ] इसे इस रूप में लिखें: [ M(x,y)dx + N(x,y)dy = 0 ] जहाँ, [ M(x,y) = x^2y - 2xy^2, \quad N(x,y) = -(x^3 - 3x^2y) = -x^3 + 3x^2y ] अब देखें कि यह अवकल समीकरण सटीक (exact) है या नहीं। सटीकता की जाँच के लिए: [ \frac{\partial M}{\partial y} \stackrel{?}{=} \frac{\partial N}{\partial x} ] [ \frac{\partial M}{\partial y} = \frac{\partial}{\partial y}(x^2y - 2xy^2) = x^2 - 4xy ] [ \frac{\partial N}{\partial x} = \frac{\partial}{\partial x}(-x^3 + 3x^2y) = -3x^2 + 6xy ] चूँकि [ \frac{\partial M}{\partial y} \neq \frac{\partial N}{\partial x} ] इसलिए समीकरण सटीक नहीं है। अब इंटीग्रिंग फैक्टर ढूंढते हैं। यहाँ ( \frac{N_x - M_y}{M} ) देखें: [ N_x - M_y = (-3x^2 + 6xy) - (x^2 - 4xy) = -4x^2 + 10xy ] [ \frac{N_x - M_y}{M} = \frac{-4x^2 + 10xy}{x^2y - 2xy^2} = \frac{-4x + 10y}{x - 2y} \quad (\text{y से बाहर काटकर}) ] यह केवल (x) और (y) के सरल अनुपात में नहीं है, इसलिए मान लें कि इंटीग्रेटिंग फैक्टर ( \mu = \frac{1}{x} )। समीकरण को (\frac{1}{x}) से गुणा करें: [ \left( x y - 2 y^2 \right) dx + \left( -x^2 + 3xy \right) dy = 0 ] अब ( M = xy - 2y^2, \quad N = -x^2 + 3xy ) जाँच करें: [ M_y = x
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