Question
Let x be the size of a certain population of predators and y the size of the population of prey upon which they feed. As function of time t, x = t 2 + 4 and
y = 2t 2 − 3t . Let u be the number of prey to each predator. Find the rate of change of u .
Answer :
Word Count : 338
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Skip in 10
The given problem describes a predator-prey system where: - \( x(t) \) represents the population of predators. - \( y(t) \) represents the population of prey. - The functions describing their population sizes are: \[ x(t) = t^2 + 4 \] \[ y(t) = 2t^2 - 3t \] You are asked to find the rate of change of \( u \), which is the number of prey per predator, given by: \[ u(t) = \frac{y(t)}{x(t)} \] ### Step 1: Define \( u(t) \) We have: \[ u(t) = \frac{y(t)}{x(t)} = \frac{2t^2 - 3t}{t^2 + 4} \] ### Step 2: Differentiate \( u(t) \) with respect to time \( t \) To find the rate of change of \( u \), we differentiate it using the quotient rule. The
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