Question
Calculate the work done by a force F = 2xˆi + 3 y ˆj in moving a particle once counter- clockwise along the ellipse
x2/4 + y2/9 = 1 . What do you understand from the answer?
Answer :
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Skip in 10
To calculate the work done by the force on a particle moving counterclockwise along the ellipse, we need to perform a line integral of the force vector field along the path defined by the ellipse. ### Problem breakdown: 1. Force vector: The given force is: \[ \mathbf{F} = 2x \, \hat{i} + 3y \, \hat{j} \] 2. Path (Ellipse): The equation of the ellipse is: \[ \frac{x^2}{4} + \frac{y^2}{9} = 1 \] This describes
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