Question
The Lagrangian of a bead of m moving without friction along a wire bent in the shape of a parabola in the X-Y pane with is given by:
Answer :
Word Count : 219
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The Lagrangian of the bead is given as: [ L = \frac{1}{2} m (1 + 4x^2) \dot{x}^2 - mg x^2 ] We solve using the Euler-Lagrange equation: [ \frac{d}{dt} \left( \frac{\partial L}{\partial \dot{x}} \right) - \frac{\partial L}{\partial x} = 0 ] First, calculate the partial derivatives. 1. Partial derivative w.r.t (\dot{x}): [ \frac{\partial L}{\partial \dot{x}} = m
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