IGNOU BCHCT 137 2026 - The density and cell-edge length of potassium chloride (KCl) are

Question

The density and cell-edge length of potassium chloride (KCl) are $1.99 \times 10^3\ \text{kg m}^{-3}$ and $6.29 \times 10^{-10}\ \text{m}$ , respectively. Using these data, determine the number of formula units per unit cell of potassium chloride crystal.

10 Jan 2026

Answer :

Word Count : 229

To determine the number of formula units per unit cell of potassium chloride (KCl), we need to use the relationship between the density, molar mass, Avogadro’s number, and the unit cell volume. The general formula is: [ Z = \frac{\rho \cdot N_A \cdot a^3}{M} ] Where: * (Z) = number of formula units per unit cell * (\rho) = density of KCl * (N_A) = Avogadro’s

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