Question
Show that the Series converges for |z| < 1 and find its sum.
Answer :
Word Count : 120
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Consider the series: [ \sum_{n=1}^{\infty} z^n (1-z) ] We can factor out ((1-z)) from the series: [ (1-z) \sum_{n=1}^{\infty} z^n ] Now, the remaining series (\sum_{n=1}^{\infty} z^n) is a geometric series with first term (z) and common ratio
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