Question
Show that for any stationary state of a symmetric potential well: .
Answer :
Word Count : 195
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For a symmetric potential well (V(x)=V(-x)), the stationary states are eigenstates of the Hamiltonian and can always be chosen to have definite parity, i.e., the wave function (\psi(x)) is either even or odd. In either case, the probability density (|\psi(x)|^2) is an even function of (x), since (|\psi(-x)|^2=|\psi(x)|^2). The expectation value of (x^2) in a stationary state is [ \langle x^2\rangle=\int_{-\infty}^{\infty} x^2
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