Question

 Show that the equation X3 + X2 - 2X - 2 = 0 has a real root other than X = -1.

13 Feb 2018
Answer :
Word Count : 301

To show that the equation \(X^3 + X^2 - 2X - 2 = 0\) has a real root other than \(X = -1\), we can use the Intermediate Value Theorem, which states that if a real-valued function is continuous on a closed interval \([a, b]\) and takes on different signs at the endpoints (\(f(a) < 0\) and \(f(b) > 0\) or vice versa), then there exists at least one real root in the open interval \((a, b)\).

In this case, we want to find a real interval \([a, b]\) such that the function \(f(X) = X^3 + X^2 - 2X - 2\) takes on different signs at the endpoints and contains

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