Question

  Prove that a strictly decreasing function is always one-one.

24 Mar 2026
Answer :
Word Count : 147
Let ( f ) be a strictly decreasing function. By definition, for any two points ( x_1 ) and ( x_2 ) in the domain of ( f ) with ( x_1 < x_2 ), we have [ f(x_1) > f(x_2). ] To prove ( f ) is one-one, we need to show that if ( f(x_1) = f(x_2)
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