Question
Prove that .
Answer :
Word Count : 143
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We are asked to prove numerically that: [ \mu^2 = 1 + \frac{\delta^2}{4}. ] Consider the quadratic equation in standard form: [ x^2 - 2x + 1 + \frac{\delta^2}{4} = 0. ] Here, comparing with the standard quadratic (x^2 - 2\mu x + 1 = 0), we have the root relation: [ \mu^2
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