Question

For the following frequency table obtain the relative frequencies and the cumulative frequencies of the ‘more than’ type.

Life (in hours)

 

499.5 – 649.5

Frequency

 

5

649.5 – 799.5

20

799.5 – 949.5

40

949.5 – 1099.5

81

1099.5 – 1249.5

57

1249.5 – 1399.5

34

1399.5 – 1549.5

13

Total

250

Also determine the number of bulbs having a life of 1249.5 hours or less.

14 Feb 2018
Answer :
Word Count : 265
First, we calculate the relative frequencies by dividing each class frequency by the total frequency $N = 250$: $$ \text{Relative frequency} = \frac{\text{Frequency}}{\text{Total frequency}} $$ | Life (hours) | Frequency | Relative Frequency | | --------------- | --------- | ------------------ | | 499.5 – 649.5 | 5 | $5/250 = 0.02$ | | 649.5 – 799.5 | 20 | $20/250 = 0.08$ | | 799.5 – 949.5 | 40 | $40/250 = 0.16$ | | 949.5 – 1099.5 | 81 | $81/250 = 0.324$ | | 1099.5 – 1249.5 |
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