Question
In an iron determination from the same amount of sample, the five replicate results were obtained: 20.1, 19.6, 20.0 and 19.9 and 20.4 mg iron.
Calculate the standard deviation, variance, standard deviation of mean, coefficient of variation and relative standard deviation in ppm of the given data.
Answer :
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Skip in 10
First, we list the data points: 20.1, 19.6, 20.0, 19.9, and 20.4 mg. Step 1: Calculate the mean ((\bar{x})) [ \bar{x} = \frac{20.1 + 19.6 + 20.0 + 19.9 + 20.4}{5} = \frac{99.9}{5} = 19.98 , \text{mg} ] Step 2: Calculate deviations from the mean and square them [ (20.1 - 19.98)^2 = (0.12)^2 = 0.0144 ] [ (19.6 - 19.98)^2 = (-0.38)^2 = 0.1444 ]
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