Question

Identify the design given in the following table and then carry out the analysis:

Column Row      
  I II III IV
I A 8 C 18 B 11 D 8
II C 16 B 10 D 7 A 4
III B 12 D 10 A 6 C 20
IV D 10 A 9 C 28 B 16
19 Jan 2026
Answer :
Word Count : 716
The given table represents a two-factor factorial design with four levels for each factor. Factor A has levels I, II, III, IV for rows, and Factor B has levels I, II, III, IV for columns. The numbers in each cell represent the observed response, while the letters indicate a treatment combination label. First, we extract the observed values in a clear matrix format: | | I | II | III | IV | | --- | -- | -- | --- | -- | | I | 8 | 18 | 11 | 8 | | II | 16 | 10 | 7 | 4 | | III | 12 | 10 | 6 | 20 | | IV | 10 | 9 | 28 | 16 | Step 1: Compute the row totals and column totals * Row totals: * I: 8 + 18 + 11 + 8 = 45 * II: 16 + 10 + 7 + 4 = 37 * III: 12 + 10 + 6 + 20 = 48 * IV: 10 + 9 + 28 + 16 = 63 * Column totals: * I: 8 + 16 + 12 + 10 = 46 * II: 18 + 10 + 10 + 9 = 47 * III: 11 + 7 + 6 + 28 = 52 * IV: 8 + 4 + 20 + 16 = 48 * Grand total (G = 45 + 37 + 48 + 63 = 193) Step 2: Compute total sum of
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