A parallel plate capacitor is made of two rectangular aluminium sheets of lateral dimensions 500 mm and 20 mm. The space between the plates is filled with
polystyrene and the separation between plates is 0.15 mm. Calculate the capacitance of the capacitor and the value of the maximum potential difference that can be applied across the capacitor without dielectric breakdown. Take the dielectric constant of polystyrene as 2.6 and the value of the maximum electric field that
polystyrene can withstand as 25×106 Vm−1.
a) The capacitance of the parallel plate capacitor filled with dielectric between its plates can be calculated from the formula:
here,
is the dielectric constant of polystyrene, 
is the permittivity of free space,
is the area of overlap of
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An electron and a proton, moving with equal velocity, enter a region of uniform, perpendicular magnetic field. Calculate the ratio of the radii of their circular paths in
the field.
A parallel plate capacitor is made of two rectangular aluminium sheets of lateral dimensions 500 mm and 20 mm. The space between the plates is filled with
polystyrene and the separation between plates is 0.15 mm. Calculate the capacitance of the capacitor and the value of the maximum potential difference that can be applied across the capacitor without dielectric breakdown. Take the dielectric constant of polystyrene as 2.6 and the value of the maximum electric field that
polystyrene can withstand as 25×106 Vm−1.
Explain the terms polarisation surface charges and molecular polarisability for a
dielectric material.
Using Maxwell’s equations in free space, derive the wave equation for the
electric field vector. Obtain the conditions under which the following time varying electric and magnetic fields satisfy Maxwell’s equations in vacuum with no source charges or currents:
E = kˆ E0 sin ( y − vt)
B = ˆi B0 sin ( y − vt)
where E0 and B0 are constant.
State and explain the boundary condition for the displacement vector D at the
boundary separating two dielectric media.
The line density of charge in a wire is 0.2 Cm−1. If this wire is symmetrically enclosed, along its length, by a cylindrical surface of radius 1 m and length 1.5 m, calculate i) the electric flux through the cylindrical surface, and ii) the electric field
at the curved surface of the cylinder.
The magnitude of work done in taking a unit positive charge in electric field E from point A to point B is given by:
Show that the value of the line integral of the electric field (right hand side of the above equation) does not depend on the path taken to move the unit positive charge
from point A to B.