IGNOU MTE 14 2018 - The motion of a simple pendulum is described byFind a solution of

Question

The motion of a simple pendulum is described by
$\frac{d^{2}\theta }{dt^{2}} + \frac{g}{1}\theta = 0$
Find a solution of the above problem in the following two situations.
i) pendulum being released from a point with angular distance $\frac{\pi }{4}$ and initial velocity zero.
ii) the bob of the pendulum is at the equilibrium position and the initial velocity is $\frac{\omega }{2}.$

15 Feb 2018

Answer :

Word Count : 220

The equation given for the simple pendulum appears to be: \[ \frac{d^{2}\theta }{dt^{2}} + g\theta = 0 \] However, there seems to be a typo with "g/1". Assuming the equation should be: \[ \frac{d^{2}\theta }{dt^{2}} + \frac{g}{L} \theta = 0 \] where $ L $ is the length of the pendulum. This is a simple

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