Question
The energy of a particle of mass m bound by a special kind of spring is
E = p2/2m + kx4
where k is a positive constant. Use the Heisenberg’s Uncertainty Principle to calculate the minimum possible energy of the particle.
Answer :
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We will use Heisenberg's Uncertainty Principle to estimate the minimum possible energy of the particle bound by the potential \( V(x) = kx^4 \). ### Step 1: Express Energy in Terms of Uncertainty The total energy is: \[ E = \frac{p^2}{2m} + kx^4 \] From Heisenberg's Uncertainty Principle, the minimum uncertainty is: \[ \Delta x \cdot \Delta p \approx \frac{\hbar}{2} \] Since we are estimating the minimum energy, we assume \( p \sim \Delta p \) and \( x \sim \Delta
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