Question
Explain how the expression for the energy levels obtained by solving Klein Gordon equation for a Coulomb field differs from the results derived from Schrödinger equation. Why is this solution not able to explain the fine-structure splitting of the energy levels?
Answer :
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The Klein-Gordon equation describes spin-0 relativistic particles and is given by [ \left[ \frac{1}{c^2} \frac{\partial^2}{\partial t^2} - \nabla^2 + \frac{m^2 c^2}{\hbar^2} \right] \psi = 0 ] For a particle in a Coulomb potential (V(r) = -\frac{Ze^2}{r}), the equation modifies to [ \left[ \left(E - V(r)\right)^2 - (pc)^2 - (mc^2)^2 \right] \psi = 0 ] Solving this equation using separation of variables in spherical coordinates, the energy eigenvalues are obtained as [ E_n = mc^2 \left[ 1 + \frac{Z^2 \alpha^2}{\left( n - \frac{1}{2} + \sqrt{\left(l + \frac{1}{2}\right)^2 - Z^2 \alpha^2} \right)^2} \right]^{-1/2} ] where (n = 1, 2, 3, \dots) is the principal quantum number, (l = 0, 1, 2, \dots, n-1) is the orbital angular momentum quantum number, and (\alpha = \frac{e^2}{\hbar c}) is the fine-structure constant.
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