Question
Solve the system of equations
3x + 2y + 4z = 7
2x + y + z = 7
x + 3y + 5z = 2
with partial pivoting. Store the multipliers and also write the pivoting vectors.
Answer :
Word Count : 567
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Skip in 10
Perform partial-pivot Gaussian elimination and store multipliers. System: 3x + 2y + 4z = 7 2x + y + z = 7 x + 3y + 5z = 2 Step 1 — column 1: pivot candidates |3|,|2|,|1| → maximum is 3 at row 1, no swap. Pivot row = 1. Multipliers (column 1): m21 = a21/a11 = 2/3, m31 = a31/a11 = 1/3. Eliminate: R2 ← R2 − (2/3)R1: R2: \[2,1,1 |7] − (2/3)\[3,2,4 |7] = \[0, −1/3, −5/3 | 7/3]. R3 ← R3 − (1/3)R1: R3: \[1,3,5 |2] − (1/3)\[3,2,4 |7] = \[0, 7/3, 11/3 | −1/3]. After step 1 matrix: \[ 3 2 4 | 7 ] \[ 0 −1/3 −5/3 | 7/3 ] \[ 0 7/3 11/3 | −1/3 ] Step 2 — column 2 (rows 2–3): compare |−1/3| and |7/3| → maximum is 7/3 at row 3, so swap row2 ↔ row3. Record pivot swap. Pivot vector after this swap (final row order) = \[1, 3, 2]. After swap: R1: \[3, 2, 4 | 7] R2: \[0, 7/3, 11/3 | −1/3] (was R3) R3: \[0, −1/3, −5/3 | 7/3] (was R2) Pivot a22 = 7/3. Multiplier: m32 = a32/a22 = (−1/3)/(7/3) = −1/7. Eliminate:
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