Question
Electrons are accelerated through a potential 150 V and incident on a crystal with interatomic spacing . Calculate the de Broglie wavelength and the first-order Bragg diffraction angle.
Answer :
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The de Broglie wavelength of an electron is given by [ \lambda = \frac{h}{p} ] where (h = 6.626 \times 10^{-34} , \text{Js}) and (p) is the momentum of the electron. The momentum can be related to the accelerating voltage (V) by [ p = \sqrt{2 m e V} ] with (m = 9.11 \times
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