The Tower of Hanoi is a classic recursive problem used in Algorithm Design Lab to demonstrate recursion, divide-and-conquer thinking, and systematic generation of moves. The problem consists of three rods, usually named Source, Auxiliary, and Destination, and a set of disks of different sizes. Initially, all disks are placed on the Source rod in decreasing order of size, with the largest disk at the bottom and the smallest disk at the top. The objective is to move the entire stack from the Source rod to the Destination rod while following three important rules: only one disk can be moved at a time, only the top disk of a rod can be moved, and a larger disk can never be placed on a smaller disk. For an Algorithm Design Lab implementation, the Tower of Hanoi can be solved efficiently using a recursive algorithm. If there are `n` disks, the problem is divided into three smaller operations. First, the top `n-1` disks are moved from the Source rod to the Auxiliary rod. Second, the largest disk is moved directly from the Source rod to the Destination rod. Third, the `n-1` disks are moved from the Auxiliary rod to the Destination rod. The same procedure is recursively applied until only one disk remains. When there is only one disk, it can be moved directly from the Source to the Destination. The recursive algorithm can be represented as follows: ```text TOH(n, Source, Auxiliary, Destination) If n = 1 Display "Move disk 1 from Source to Destination" Return TOH(n-1, Source, Destination, Auxiliary) Display "Move disk n from Source to Destination" TOH(n-1, Auxiliary, Source, Destination) ``` The algorithm begins by checking whether `n` is equal to 1. If it is, the algorithm displays the single required move and terminates that recursive call. If `n` is greater than 1, the algorithm first solves the problem for `n-1` disks. The roles of the rods are changed during recursive calls because the Auxiliary rod temporarily becomes